Ans: D
According to the given system of equations, $\alpha$ and $\beta$ are the roots of $3x=x^2-5$. Therefore, we have
According to the given system of equations, $\alpha$ and $\beta$ are the roots of $3x=x^2-5$. Therefore, we have
$\begin{array}{rcl}
3x & = & x^2 – 5 \\
x^2 -3x – 5 & = & 0
\end{array}$
Hence,
$\begin{array}{rcl}
\alpha\beta & = & \dfrac{-5}{1} \\
& = & -5
\end{array}$
