Ans: (a) $(a+1)(a-3)$ (b) $(a+1)(b^2+a-3)$
-
$\begin{array}{cl}
& a^2 – 2a – 3\\
= & (a+1)(a-3)
\end{array}$ -
$\begin{array}{cl}
& ab^2 +b^2 +a^2 – 2a -3 \\
= & b^2 ( a+1) + (a+1)(a-3) \\
= & (a+1) (b^2 + a – 3)
\end{array}$
