Ans: median $=1$, mode $=2$, standard deviation $=0.889$
Note that there are $40$ students in the distribution. Therefore, the median is the average of the data of the $20$th and $21$th students. Hence, we have
Note that there are $40$ students in the distribution. Therefore, the median is the average of the data of the $20$th and $21$th students. Hence, we have
$\begin{array}{rcl}
\text{the median} & = & \dfrac{1+1}{2} \\
& = & 1
\end{array}$
Note that the mode is the data with the highest frequency in the distribution. Hence, the mode is $2$.
By using the calculator, the standard deviation is $0.889$.
