Ans: A
$\begin{array}{cl}
& u^2 – v^2 -5u + 5v \\
= & (u+v)(u-v) -5(u-v) \\
= & (u-v)(u+v-5)
\end{array}$
$\begin{array}{cl}
& u^2 – v^2 -5u + 5v \\
= & (u+v)(u-v) -5(u-v) \\
= & (u-v)(u+v-5)
\end{array}$
Resources for HKDSE Mathematics
Resources for HKDSE Mathematics
