2014-II-14

Ans: D
By the given formula, we have

$\left\{ \begin{array}{ll}
a_5 = a_4 + a_3 & \ldots \unicode{x2460} \\
a_4 = a_3 + a_2 & \ldots \unicode{x2461}
\end{array} \right.$

$\unicode{x2460} – \unicode{x2461}$, we have

$\begin{array}{rcl}
a_5 – a_4 & = & ( a_4 + a_3) – (a_3 + a_2) \\
a_5 – a_4 & = & a_4 – a_2 \\
a_5 & = & 2a_4 -a_2 \\
a_5 & = & 2(63) – 7 \\
a_5 & = & 119
\end{array}$