2014-II-14 Posted on 16-06-2021 By app.cch No Comments on 2014-II-14 Ans: DBy the given formula, we have ①②{a5=a4+a3…①a4=a3+a2…② ①②①–②, we have a5–a4=(a4+a3)–(a3+a2)a5–a4=a4–a2a5=2a4−a2a5=2(63)–7a5=119 Same Topic: 2014-I-16 2014-II-37 2022-I-17 2022-II-14 2014, HKDSE-MATH, Paper 2 Tags:Sequences