Ans: B
I may not be true. The greatest possible value of $h$ is $4$.
I may not be true. The greatest possible value of $h$ is $4$.
II must be true. Note that the range of the distribution is at least $33$. For $h=0$, which is the least possible value of $h$, we have
$\begin{array}{rcl}
(40 + k) – 10 & \ge & 33 \\
k & \ge & 3
\end{array}$
Note also that $k \le 9$. Therefore, we have $3 \le k \le 9$.
III may not be true. For $h=0$ and $k=9$, we have
$\begin{array}{rcl}
k – h & = & 9 – 0 \\
k – h & = & 9
\end{array}$
And for $h=0$ and $k=3$, we have
$\begin{array}{rcl}
k – h & = & 3 – 0 \\
k – h & = & 3
\end{array}$
Therefore, $3 \le k-h \le 9$.
