Ans: C
$\begin{array}{cl}
& 7\times 2^{10} + 2^8 + 5\times 2^3 – 2^3 \\
= & (4 + 2 + 1) \times 2^{10} + 2^8 + (4+1) \times 2^3 -2^3 \\
= & 4 \times 2^{10} + 2 \times 2^{10} + 1 \times 2^{10} + 1 \times 2^8 + 4 \times 2^3 + 1 \times 2^3 – 1 \times 2^3 \\
= & 1 \times 2^{12} + 1 \times 2^{11} + 1\times 2^{10} + 1 \times 2^8 + 1 \times 2^5 \\
= & 1\ 110\ 100\ 100\ 000_2
\end{array}$
$\begin{array}{cl}
& 7\times 2^{10} + 2^8 + 5\times 2^3 – 2^3 \\
= & (4 + 2 + 1) \times 2^{10} + 2^8 + (4+1) \times 2^3 -2^3 \\
= & 4 \times 2^{10} + 2 \times 2^{10} + 1 \times 2^{10} + 1 \times 2^8 + 4 \times 2^3 + 1 \times 2^3 – 1 \times 2^3 \\
= & 1 \times 2^{12} + 1 \times 2^{11} + 1\times 2^{10} + 1 \times 2^8 + 1 \times 2^5 \\
= & 1\ 110\ 100\ 100\ 000_2
\end{array}$
