Ans: $\dfrac{3}{10}$
Note that the sample space is as follow:
Note that the sample space is as follow:
$\begin{array}{|c|c|c|c|c|c|} \hline
& 2 & 4 & 6 & 8 & 10 \\ \hline
1 & 3 & 5 & 7 & 9 & 11 \\ \hline
3 & 5 & 7 & 9 & 11 & 13 \\ \hline
5 & 7 & 9 & 11 & 13 & 15 \\ \hline
7 & 9 & 11 & 13 & 15 & 17 \\ \hline
\end{array}$
The required probability
$\begin{array}{cl}
= & \dfrac{6}{20} \\
= & \dfrac{3}{10}
\end{array}$
