Ans: (a) $x > \dfrac{13}{4}$ (b) $4$
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$\begin{array}{rcl}
\dfrac{7-3x}{5} & \le & 2(x+2) \\
7-3x & \le & 10(x+2) \\
7-3x & \le & 10x + 20 \\
-13x & \le & 13 \\
x & \ge & -1
\end{array}$Also,
$\begin{array}{rcl}
4x-13 & > & 0 \\
4x & > & 13 \\
x & > & \dfrac{13}{4}
\end{array}$Therefore, $x\ge -1$ and $x > \dfrac{13}{4}$.
Hence, we have $x>\dfrac{13}{4}$.
- $4$
