Ans: A
Since $\beta$ is a root of the equation $4x^2 -5x – 1=0$, then we have
Since $\beta$ is a root of the equation $4x^2 -5x – 1=0$, then we have
$\begin{array}{rcl}
4\beta^2 -5\beta -1 & = & 0 \\
8\beta^2 -10\beta -2 & = & 0 \\
2 + 10 \beta – 8\beta^2 & = & 0 \\
7 + 10 \beta – 8\beta^2 & = & 5
\end{array}$
