Ans: B
For $m=3$, the mean $p$
For $m=3$, the mean $p$
$\begin{array}{cl}
= & \dfrac{2+2+3+\cdots + 9 + 10}{15} \\
= & 4.87
\end{array}$
For $m=4$, the mean $p$
$\begin{array}{cl}
= & \dfrac{2+2+3+\cdots + 9 + 10}{15} \\
= & 4.93
\end{array}$
For $m=5$, the mean $p$
$\begin{array}{cl}
= & \dfrac{2+2+3+\cdots+9+10}{15} \\
= & 5
\end{array}$
For $3\le m \le 5$, the median $q=m$.
For $3\le m \le 5$, the mode $r=3$.
Hence, we have the following result.
I may not be true. If $m=5$, $p=q$.
II must be true.
III may not be true. If $m=3$, $q=r$.
