Ans: (a) $x=6$, $y=22$, $z=40$ (b) $\dfrac{2}{5}$
- By comparing the first row of two tables, $a=2$.
$\begin{array}{rcl}
x & = & a + 4 \\
x & = & 2 + 4 \\
x & = & 6
\end{array}$$\begin{array}{rcl}
b & = & 13 – x \\
b & = & 13 – 6 \\
b & = & 7
\end{array}$$\begin{array}{rcl}
z & = & 37 + 3 \\
z & = & 40
\end{array}$$\begin{array}{rcl}
c & = & 40 – 3 – 15 – 7 – 4 – 2 \\
c & = & 9
\end{array}$$\begin{array}{rcl}
y & = & 13 + c \\
y & = & 13 + 9 \\
y & = & 22
\end{array}$Therefore $x=6$, $y=22$ and $z=40$.
- $P\text{(the height of the selected plant is less than $1.25$ m but not less than $0.65$ m)}$
$\begin{array}{cl}
= & \dfrac{22 – 6}{40} \\
= & \dfrac{2}{5}
\end{array}$
