Ans: D
$\begin{array}{rcl}
(3y-4x):(2x+y) & = & 5:6 \\
\dfrac{3y-4x}{2x+y} & = & \dfrac{5}{6} \\
18y -24x & = & 10x + 5y \\
34x & = & 13y \\
\dfrac{x}{y} & = & \dfrac{13}{34} \\
x:y & = & 13 : 34
\end{array}$
$\begin{array}{rcl}
(3y-4x):(2x+y) & = & 5:6 \\
\dfrac{3y-4x}{2x+y} & = & \dfrac{5}{6} \\
18y -24x & = & 10x + 5y \\
34x & = & 13y \\
\dfrac{x}{y} & = & \dfrac{13}{34} \\
x:y & = & 13 : 34
\end{array}$
