Ans: (a) $\dfrac{5}{3876}$ (b) $\dfrac{35}{969}$ (c) $\dfrac{3731}{3876}$
- The required probability
$\begin{array}{cl}
= & \dfrac{C^4_4\times C^{15}_1}{C^{19}_5} \\
= & \dfrac{5}{3876}
\end{array}$ - The required probability
$\begin{array}{cl}
= & \dfrac{C^4_3 \times C^{15}_1}{C^{19}_5} \\
= & \dfrac{35}{969}
\end{array}$ - The required probability
$\begin{array}{cl}
= & 1- \dfrac{5}{3876} – \dfrac{35}{969} \\
= & \dfrac{3731}{3876}
\end{array}$
