2017-II-03

Ans: A
$\begin{array}{rcl}
\dfrac{a+4b}{2a} & = & 2 + \dfrac{b}{a} \\
\dfrac{a+4b}{2a} & = & \dfrac{2a + b}{a} \\
a + 4b & = & 2(2a+b) \\
a + 4b & = & 4a + 2b \\
3a & = & 2b \\
a & = & \dfrac{2b}{3}
\end{array}$