Ans: D
Consider $6-x < 2x -3$.
Consider $6-x < 2x -3$.
$\begin{array}{rcl}
6 – x & < & 2x - 3 \\
9 & < & 3x \\
x & > & 3
\end{array}$
Consider $7-3x>1$.
$\begin{array}{rcl}
7 – 3x & > & 1 \\
-3x & > & -6 \\
x & < & 2
\end{array}$
Therefore, the overall solution is $x<2$ or $x>3$.
