Ans: B
Since $p(x)$ is divisible by $x-7$, then by the factor theorem, we have
Since $p(x)$ is divisible by $x-7$, then by the factor theorem, we have
$\begin{array}{rcl}
p(7) & = & 0 \\
2(7)^2 -11(7) + c & = & 0 \\
c & = & -21
\end{array}$
Therefore, $p(x) = 2x^2 -11x – 21$.
By the remainder theorem, the required remainder
$\begin{array}{cl}
= & p(\dfrac{-1}{2}) \\
= & 2(\dfrac{-1}{2})^2 – 11(\dfrac{-1}{2}) – 21 \\
= & -15
\end{array}$
