Ans: C
Consider the function of the graph.
Consider the function of the graph.
$\begin{array}{rcl}
y & = & (px+5)^2 +q \\
y & = & [p(x + \dfrac{5}{p})]^2 + q \\
y & = & p^2(x – \dfrac{-5}{p})^2 + q
\end{array}$
Therefore, the coordinates of vertex of the graph are $(\dfrac{-5}{p}, q)$.
Note that the vertex of the graph lies in quadrant III. Then we have
$\begin{array}{rcl}
\dfrac{-5}{p} & < & 0 \\
p & > & 0
\end{array}$
and also
$\begin{array}{rcl}
q & < & 0
\end{array}$
Therefore, $p>0$ and $q<0$.
