Ans: C
By applying intercept form to the given figure, we have
By applying intercept form to the given figure, we have
$\begin{array}{rcl}
\dfrac{x}{4} + \dfrac{\sqrt{y}}{8} & = & 1 \\
2x + \sqrt{y} & = & 8 \\
\sqrt{y} & = & 8 – 2x \\
y & = & (8-2x)^2 \\
y & = & 4x^2 – 32x + 64
\end{array}$
