2018-II-13

$\begin{array}{rcl}
\dfrac{1-2x}{3} & \ge & x – 3 \\
1 – 2x & \ge & 3x – 9 \\
-5x & \ge & -10 \\
x & \le & 2
\end{array}$

Consider

$\begin{array}{rcl}
4x + 9 & < & 1 \\ 4x & < & -8 \\ x & < & -2 \end{array}$

Therefore, $x \le 2$ or $x < -2$.

Hence, the overall solution is $x \le 2$.