Ans: B
Consider the first inequality.
Consider the first inequality.
$\begin{array}{rcl}
-2(x – 5) + 5 & < & 21 \\
-2x + 10 + 5 & < & 21 \\
-2x & < & 6 \\
x & > & -3
\end{array}$
Consider the second inequality.
$\begin{array}{rcl}
\dfrac{3x – 5}{7} & > & 1 \\
3x – 5 & > & 7 \\
3x & > & 12 \\
x & > & 4
\end{array}$
Therefore, $x > -3$ or $x > 4$.
Hence, the overall solution is $x > -3$.
Therefore, the least integer is $-2$.
