2019-II-42 Posted on 16-06-2021 By app.cch No Comments on 2019-II-42 Ans: CThe required probability $\begin{array}{cl} = & 1 – \dfrac{C^{11}_6}{C^{19}_6} \\ = & \dfrac{635}{646} \end{array}$ Same Topic: 2019-I-08 2019-I-15 2019-II-28 2019-II-43 2019, HKDSE-MATH, Paper 2 Tags:Probability