Ans: (a) $(\alpha + 3)(\alpha -2)$ (b) $\alpha^2(\alpha + 3)(\alpha -2)$
-
$\begin{array}{cl}
& \alpha^2 + \alpha – 6 \\
= & (\alpha + 3)(\alpha – 2)
\end{array}$ -
$\begin{array}{cl}
& \alpha^4 + \alpha^3 -6\alpha^2 \\
= & \alpha^2(\alpha^2 + \alpha -6) \\
= & \alpha^2(\alpha + 3)(\alpha – 2)
\end{array}$
