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2020-II-24

Posted on 16-06-202114-06-2023 By app.cch No Comments on 2020-II-24
Ans: D
Since the coordinates of the reflection image of $Q$ with respect to the $y$-axis are $(5,-1)$, then the coordinates of $Q$ are $(-5,-1)$.

Since $P$ is translated leftwards by $4$ units to $Q$, then the coordinates of $P$ are $(-1, -1)$.

By Pythagoras Theorem, we have

$\begin{array}{rcl}
OP^2 & = & 1^2 + 1^2 \\
OP^2 & = & 2 \\
OP & = & \sqrt{2}
\end{array}$

Also, we have

$\begin{array}{rcl}
\tan \theta & = & \dfrac{1}{1} \\
\tan \theta & = & 1 \\
\theta & = & 45^\circ
\end{array}$

Therefore, the polar coordinates of $P$ are $(\sqrt{2}, 45^\circ + 180^\circ)$, i.e. $(\sqrt{2}, 225^\circ)$.

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2020, HKDSE-MATH, Paper 2 Tags:Coordinates

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3D Problems (41) Basic Functions (13) Basic Geometry (68) Binomial Theorem (7) Change of Subject (32) Complex Numbers (16) Coordinates (46) Differentiation (16) Equations of Circle (54) Equations of Straight Line (43) Estimations and Errors (35) Factorization (39) Graph of Functions (3) Inequality (39) Integration (15) Laws of Indices (43) Linear Programming (21) Locus (13) Logarithm (34) Mathematical Induction (7) Matrices (4) Mensuration (98) Numeral System (19) Percentage (42) Polynomials (49) Probability (85) Properties of Circles (56) Quadratic Equations and Functions (57) Rate and Ratio (30) Rational Functions (20) Sequences (66) Simultaneous Linear Equations (27) Statistics (122) System of Linear Equations (3) Transformations (44) Trigonometry (M2) (7) Trigonometry and Its Applications (67) Variations (38) Vectors (3)

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