Ans: D
The slope of $L$
The slope of $L$
$\begin{array}{cl}
= & \dfrac{-k}{4}
\end{array}$
The slope of the straight line $6x-9y+4=0$
$\begin{array}{cl}
= & \dfrac{6}{9} \\
= & \dfrac{2}{3}
\end{array}$
Since $L$ is perpendicular to the straight line $6x – 9y + 4 = 0$, then we have
$\begin{array}{rcl}
\dfrac{-k}{4} \times \dfrac{2}{3} & = & -1 \\
k & = & 6
\end{array}$
Therefore, the equation of $L$ is $6x+4y-12=0$.
Hence, the $y$-intercept of $L$
$\begin{array}{cl}
= & \dfrac{12}{4} \\
= & 3
\end{array}$
