Ans: C
By the intercepts form, the equation of the straight line is
By the intercepts form, the equation of the straight line is
$\begin{array}{rcl}
\dfrac{x^3}{-4} + \dfrac{\sqrt{y}}{1} & = & 1 \\
\dfrac{-1}{4} x^3 + \sqrt{y} & = & 1
\end{array}$
Sub. $x=2$ into the equation, we have
$\begin{array}{rcl}
\dfrac{-1}{4} (2)^3 + \sqrt{y} & = & 1 \\
\sqrt{y} & = & 3 \\
y & = & 9
\end{array}$
