Ans: D
For the accuracy correct to 2 decimal places, the maximum absolute error
$\begin{array}{cl}
= & \dfrac{1}{2} \times 0.01 \\
= & 0.005
\end{array}$
Therefore, the range of values of $x$ is
$\begin{array}{rcccl}
6.24-0.005 & \le & x & < & 6.24+0.005 \\
6.235 & \le & x & < & 6.245
\end{array}$
