Ans: C
Consider the first inequality, we have
$\begin{array}{rcl}
9x +8 & \le & 4(x-3) \\
9x +8 & \le & 4x -12 \\
5x & \le & -20 \\
x & \le & -4
\end{array}$
Consider the second inequality, we have
$\begin{array}{rcl}
6-7x & > & 20 \\
-7x & > & 14 \\
x & < & -2
\end{array}$
$\therefore x\le -4$ or $x<-2$.
Therefore, the overall solution is $x <-2$.