Ans: D
Note that there are $24$ workers. Then the lower quartile of the distribution
$\begin{array}{cl}
= & \dfrac{\text{the $6$th datum} +\text{the $7$ datum}}{2} \\
= & \dfrac{62+62}{2} \\
= & 62 \text{ kg}
\end{array}$
Hence, the required probability
$\begin{array}{cl}
= & \dfrac{20}{24} \\
= & \dfrac{5}{6}
\end{array}$
