Ans: $\dfrac{17k}{(k-9)(5k+6)}$
$\begin{array}{cl}
& \dfrac{3}{k-9}+\dfrac{2}{5k+6} \\
= & \dfrac{3(5k+6)}{(k-9)(5k+6)} +\dfrac{2(k-9)}{(k-9)(5k+6)} \\
= & \dfrac{15k +18 +2k -18}{(k-9)(5k+6)} \\
= & \dfrac{17k}{(k-9)(5k+6)}
\end{array}$
