Ans: (a) $x<-2$ (b) $-3$
- Consider the first inequality, we have
$\begin{array}{rcl}
-2(3x+2) & > & x+10\\
-6x -4 & > & x +10 \\
-7x & > & 14 \\
x & < & -2 \end{array}$Consider the second inequality, we have
$\begin{array}{rcl}
2x & \le & -8 \\
x & \le & -4
\end{array}$$\therefore$ the overall solution is $x< -2$.
- $-3$
