Ans: A
Let $r\text{ cm}$ be the radius of the the hemisphere. Then the base radius and the height of the cylinder is $r\text{ cm}$ and $2r\text{ cm}$ respectively.
$\begin{array}{cl}
& \text{total surface area of the hemisphere} : \text{total surface area of the cylinder} \\
= & \dfrac{1}{2} \times 4\pi r^2 + \pi r^2 : 2\pi r (2r) +2\pi r^2 \\
= & 3\pi r^2 :6\pi r^2 \\
= & 1:2
\end{array}$
