2022-II-23

07-07-2023 app.cch No Comments

Ans: C

Sketch the figure according to the question.

Since $P Q R S$ is a rhombus, then $P Q = Q R$ , $S T = Q T$ and $∠ Q T R = 90^{\circ}$ . Hence, we have

$\begin{array}{rcl} \frac{P Q}{S T} & = & \frac{Q R}{Q T} \\ \frac{P Q}{S T} & = & \frac{1}{\sin θ} \end{array}$