Ans: A
Note that $\alpha = \angle GFH = 45^\circ$.
Denote the mid-point of $FH$ and $AH$ be $Q$ and $P$ respectively. Then $\beta = \angle GQP =90^\circ$.
Therefore, $\alpha < 60^\circ< \beta$.
Resources for HKDSE Mathematics
Resources for HKDSE Mathematics
Note that $\alpha = \angle GFH = 45^\circ$.
Denote the mid-point of $FH$ and $AH$ be $Q$ and $P$ respectively. Then $\beta = \angle GQP =90^\circ$.
Therefore, $\alpha < 60^\circ< \beta$.
