Ans: D
Consider the first inequality, we have
$\begin{array}{rcl}
x-3 & < & -5 \\
x & < & -2
\end{array}$
Consider the second inequality, we have
$\begin{array}{rcl}
\dfrac{6-x}{4} & < & 2 \\
6-x & < & 8 \\
-x & < & 2 \\
x & > & -2
\end{array}$
Therefore, $x<-2$ or $x>-2$.
Hence, the overall solution is $x \neq -2$.
