Ans: B
$\begin{array}{rcl}
a_8 & = & a_7 +a_6 \\
60 & = & a_7 +23 \\
a_7 & = & 37
\end{array}$
Also,
$\begin{array}{rcl}
a_7 & = & a_6+a_5 \\
37 & = & 23 +a_5 \\
a_5 & = & 14
\end{array}$
Aslo,
$\begin{array}{rcl}
a_6 & = & a_5 +a_4 \\
23 & = & 14 +a_4 \\
a_4 & = & 9
\end{array}$
Therefore, we have
$\begin{array}{rcl}
a_5 & = & a_4+a_3 \\
14 & = & 9 +a_3 \\
a_3 & = & 5
\end{array}$