Ans: A
Let $r\text{ cm}$ and $h\text{ cm}$ be the base radius and the height of the right circular cylinder respectively.
Since the volume of the cube is equal to the volume of the right circular cylinder, we have
$\begin{array}{rcl}
60^3 & = & \pi r^2 h \\
\pi r^2 h & = & 216\ 000 \ldots \unicode{x2460}
\end{array}$
Since the curved surface area of the circular cylinder is equal to the total surface area of the cube, we have
$\begin{array}{rcl}
2\pi r h & = & 6 \times 60^2 \\
\pi r h & = & 10\ 800 \ldots \unicode{x2461}
\end{array}$
$\unicode{x2460} \div \unicode{x2461}$, we have $r = 20$.
Therefore, the base radius of the right circular cylinder is $20\text{ cm}$.
