2011SP-I-07
Ans: $19^\circ$
$\because AB//OC$,
… Read $\because AB//OC$,
$\begin{array}{rcl}
HKDSE-MATH - 2011SP - Paper 1 -
2011SP-I-08
Ans: (a) $A’=(5,2)$, $A”=(2,5)$ (b) No
… Read - $A
2011SP-I-09
Ans: (a) $60$ (b) No
… Read -
$\begin{array}{rcl}
x & = & 7
2011SP-I-10
Ans: (a) $5x+2$ (b) (i) $a=2$, $b=-1$ (ii) $-3$, $1$ or $\dfr
… Read 2011SP-I-11
Ans: (a) $\$1\ 644$ (b) $\dfrac{11}{4}\text{ m}$
… Read - $C=k_1s+
2011SP-I-12
Ans: (a) Part I (b) $8:26$ (c) $15\text{ m/s}$
… Read - Note that the s
2011SP-I-13
Ans: (a) $3x+4y-48=0$ (b) (i) Parallel (ii) $3x+4y-32=0$
… Read - N
2011SP-I-14
Ans: (a) Median $=62\%$, mean $=60\%$ (b) (i) $58\%$ (ii) $a
… Read 2011SP-I-15
Ans: $21$
Note that the number of seats in a row form an arithm
… Read Note that the number of seats in a row form an arithm
2011SP-I-16
Ans: (a) $\dfrac{10}{21}$ (b) $\dfrac{11}{21}$
… Read - The requi
2011SP-I-17
Ans: $9.6$
$\begin{array}{rcl}
6.4 & = & \log_8
… Read $\begin{array}{rcl}
6.4 & = & \log_8
2011SP-I-18
Ans: (a) $BC=20\sqrt{2}\text{ cm}$, $BD=10\sqrt{6}\tex
… Read 2011SP-I-19
Ans: (a) (ii) Yes (b) $y=2x+1$
… Read -
- Join $CD$.
$\angle QCD = \angl
- Join $CD$.
2011SP-II-01
Ans: C
$\begin{array}{cl}
& (3a)^2\cdot a^3 \\
=
… Read $\begin{array}{cl}
& (3a)^2\cdot a^3 \\
=
2011SP-II-02
Ans: C
$\begin{array}{rcl}
5-3m & = & 2n \\
3m �
… Read $\begin{array}{rcl}
5-3m & = & 2n \\
3m �
2011SP-II-03
Ans: C
$\begin{array}{cl}
& a^2-b^2+2b-1 \\
= &
… Read $\begin{array}{cl}
& a^2-b^2+2b-1 \\
= &
2011SP-II-04
Ans: A
$\begin{array}{rcl}
x^2+p(x+5)+q & \equiv &am
… Read $\begin{array}{rcl}
x^2+p(x+5)+q & \equiv &am
2011SP-II-05
Ans: C
According to the remainder theorem, the remainder
… Read According to the remainder theorem, the remainder
$\
2011SP-II-06
Ans: D
$\begin{array}{rcl}
(x-a)(x-a-1) & = & (x-
… Read $\begin{array}{rcl}
(x-a)(x-a-1) & = & (x-
2011SP-II-07
Ans: D
$\begin{array}{rcl}
x^2-6x & = & 2-k \\
x^2-
… Read $\begin{array}{rcl}
x^2-6x & = & 2-k \\
x^2-