2016-II-03
Ans: D
$\begin{array}{cl}
& 16 – (2x-3y)^2 \\
=
… Read $\begin{array}{cl}
& 16 – (2x-3y)^2 \\
=
HKDSE-MATH - 2016 - Paper 2 -
2016-II-04
Ans: C
$\begin{array}{cl}
& 0.076\ 540\ 3 \\
= & 0
… Read $\begin{array}{cl}
& 0.076\ 540\ 3 \\
= & 0
2016-II-05
Ans: A
$\left\{ \begin{array}{ll}
4\alpha + \beta = 5 &
… Read $\left\{ \begin{array}{ll}
4\alpha + \beta = 5 &
2016-II-06
Ans: B
Since $f(x)$ is divisible by $2x+1$, we have
… Read Since $f(x)$ is divisible by $2x+1$, we have
$\begin{
2016-II-07
Ans: A
Consider the first inequality,
… Read Consider the first inequality,
$\begin{array}{rcl
2016-II-08
Ans: C
Since the quadratic equation $x^2+kx+8k+36=0$ has e
… Read Since the quadratic equation $x^2+kx+8k+36=0$ has e
2016-II-09
Ans: D
$\begin{array}{rcl}
y & = & (ax+1)^2 + a \\
y &
… Read $\begin{array}{rcl}
y & = & (ax+1)^2 + a \\
y &
2016-II-10
Ans: C
The monthly salary of Peter
… Read The monthly salary of Peter
$\begin{array}{cl}
= �
2016-II-11
Ans: D
$\begin{array}{rcl}
(3y-4x):(2x+y) & = &
… Read $\begin{array}{rcl}
(3y-4x):(2x+y) & = &
2016-II-12
Ans: D
Let $z = \dfrac{k\sqrt{x}}{y}$, where $k$ is a non-ze
… Read Let $z = \dfrac{k\sqrt{x}}{y}$, where $k$ is a non-ze
2016-II-13
Ans: A
Let $\$y\text{ kg}$ be the cost of flour of brand $Y$.
… Read Let $\$y\text{ kg}$ be the cost of flour of brand $Y$.
$
2016-II-14
Ans: C
Note that the sequence of the number of dots in the patt
… Read Note that the sequence of the number of dots in the patt
2016-II-15
Ans: B
Add a straight line $DE$ passing through $C$ such that
… Read Add a straight line $DE$ passing through $C$ such that
2016-II-16
Ans: D
In $\Delta ABD$,
… Read In $\Delta ABD$,
$\begin{array}{rcl}
AB^2 + BD^2 �
2016-II-17
Ans: A
Since $ABCD$ is a parallelogram, then $AD\text{//}B
… Read Since $ABCD$ is a parallelogram, then $AD\text{//}B
2016-II-18
Ans: C
Add a point $E$ on $CD$ such that $BE\perp CD$.
… Read Add a point $E$ on $CD$ such that $BE\perp CD$.
Since $A
2016-II-19
Ans: A
… Read I is true. Let $\theta$ be the angle of the sector $OAB$
2016-II-20
Ans: C
… Read Since $ABCD$, $CDEF$ and $EFGH$ are squares, then we h
2016-II-21
Ans: B
… Read Add points $E$ and $F$ on $AD$ and $CD$ respectively, s
2016-II-22
Ans: D
… Read Since $ABCD$ is a rhombus, then we have $BC\text{//}A