2006-II-01
Ans: B
$\begin{array}{cl}
& (2x)^3 \cdot x^3 \\
=
… Read $\begin{array}{cl}
& (2x)^3 \cdot x^3 \\
=
$\begin{array}{rcl}
$\begin{array}{cl}
= & 1
Le
$\begin{ar
Since the bearing of $Q$ from $A$ is $\text{S}28^\cir
$\begin{array}{cl}
= & \
Join $OB$. Since $OC$ and $OB$ are radii, then $OB = 2\t
$\begin{array}{cl}
=