2011-II-01
Ans: A
$\begin{array}{cl}
& 5^{334}\left(\dfrac{-
… Read $\begin{array}{cl}
& 5^{334}\left(\dfrac{-
HKCEE - 2011 - Paper 2
2011-II-02
Ans: A
$\begin{array}{rcl}
\dfrac{2+a}{a} & = &
… Read $\begin{array}{rcl}
\dfrac{2+a}{a} & = &
2011-II-03
Ans: D
$\begin{array}{cl}
& (x-2y)(x+2y-2) \\
=
… Read $\begin{array}{cl}
& (x-2y)(x+2y-2) \\
=
2011-II-04
Ans: B
I must be true. For any non-zero numbers $x$ and $y$,
… Read I must be true. For any non-zero numbers $x$ and $y$,
$\
2011-II-05
Ans: A
$\begin{array}{rcl}
2(1-x)+5 & \ge & 17 \
… Read $\begin{array}{rcl}
2(1-x)+5 & \ge & 17 \
2011-II-06
Ans: C
Let $\$x$ and $\$y$ be the price of a pen and a pencil res
… Read Let $\$x$ and $\$y$ be the price of a pen and a pencil res
2011-II-07
Ans: A
A is true. Substitute $y=0$ into the equation of the gr
… Read A is true. Substitute $y=0$ into the equation of the gr
2011-II-08
Ans: A
$\begin{array}{cl}
& f(5)-f(3) \\
= & (5)
… Read $\begin{array}{cl}
& f(5)-f(3) \\
= & (5)
2011-II-09
Ans: B
Note that the first term is $4$ and the common differen
… Read Note that the first term is $4$ and the common differen
2011-II-10
Ans: C
The required interest
… Read The required interest
$\begin{array}{cl}
= & \
2011-II-11
Ans: B
Let $\ell_0$ and $b_0$ be the original value of the len
… Read Let $\ell_0$ and $b_0$ be the original value of the len
2011-II-12
Ans: B
$\begin{array}{rcl}
\dfrac{2m-n}{m-2n} & = &
… Read $\begin{array}{rcl}
\dfrac{2m-n}{m-2n} & = &
2011-II-13
Ans: C
Let $a=\dfrac{kb}{c^2}$, where $k$ is a non-zero con
… Read Let $a=\dfrac{kb}{c^2}$, where $k$ is a non-zero con
2011-II-14
Ans: B
According to the figure, $p\approx -4$, $q \approx -2
… Read According to the figure, $p\approx -4$, $q \approx -2
2011-II-15
Ans: A
Add a point $X$ on the figure as shown.
… Read Add a point $X$ on the figure as shown.
In $\Delta ABX$,
2011-II-16
Ans: C
Let $\theta$ be the angle at centre of the sector. Then
… Read Let $\theta$ be the angle at centre of the sector. Then
2011-II-17
Ans: C
… Read Let $x\text{ cm}$ be the length of the hypotenuse of th
2011-II-18
Ans: B
$\begin{array}{rcl}
\dfrac{1}{2} \times \dfrac{4
… Read $\begin{array}{rcl}
\dfrac{1}{2} \times \dfrac{4
2011-II-19
Ans: D
Since $ABCD$ is a parallelogram, then $AB=CD$.
… Read Since $ABCD$ is a parallelogram, then $AB=CD$.
It is g
2011-II-20
Ans: D
Note that $x+y+z=180^\circ$ and $x+y=90^\circ$. Th
… Read Note that $x+y+z=180^\circ$ and $x+y=90^\circ$. Th