2011SP-II-01
Ans: C
$\begin{array}{cl}
& (3a)^2\cdot a^3 \\
=
… Read $\begin{array}{cl}
& (3a)^2\cdot a^3 \\
=
HKDSE-MATH - 2011SP - Paper 2
2011SP-II-02
Ans: C
$\begin{array}{rcl}
5-3m & = & 2n \\
3m �
… Read $\begin{array}{rcl}
5-3m & = & 2n \\
3m �
2011SP-II-03
Ans: C
$\begin{array}{cl}
& a^2-b^2+2b-1 \\
= &
… Read $\begin{array}{cl}
& a^2-b^2+2b-1 \\
= &
2011SP-II-04
Ans: A
$\begin{array}{rcl}
x^2+p(x+5)+q & \equiv &am
… Read $\begin{array}{rcl}
x^2+p(x+5)+q & \equiv &am
2011SP-II-05
Ans: C
According to the remainder theorem, the remainder
… Read According to the remainder theorem, the remainder
$\
2011SP-II-06
Ans: D
$\begin{array}{rcl}
(x-a)(x-a-1) & = & (x-
… Read $\begin{array}{rcl}
(x-a)(x-a-1) & = & (x-
2011SP-II-07
Ans: D
$\begin{array}{rcl}
x^2-6x & = & 2-k \\
x^2-
… Read $\begin{array}{rcl}
x^2-6x & = & 2-k \\
x^2-
2011SP-II-08
Ans: A
I is correct. $f(x)>k$ means the part of $y=f(x)$ a
… Read I is correct. $f(x)>k$ means the part of $y=f(x)$ a
2011SP-II-09
Ans: C
$\begin{array}{rcl}
5-2x & < & 3 \\ -2x & < & -2 \\ x & > & 1
\end{arra
… Read $\begin{array}{rcl}
5-2x & < & 3 \\ -2x & < & -2 \\ x & > & 1
\end{arra
2011SP-II-10
Ans: A
Let $\$x$ and $\$y$ be the costs of the gained bag and th
… Read Let $\$x$ and $\$y$ be the costs of the gained bag and th
2011SP-II-11
Ans: C
$\begin{array}{rcl}
a_1 & = & 4 \\
a_2
… Read $\begin{array}{rcl}
a_1 & = & 4 \\
a_2
2011SP-II-12
Ans: B
Let $l_0$, $w_0$ and $A_0$ be the original length, wid
… Read Let $l_0$, $w_0$ and $A_0$ be the original length, wid
2011SP-II-13
Ans: D
$\begin{array}{rcl}
2x & = & 3y \\
y &
… Read $\begin{array}{rcl}
2x & = & 3y \\
y &
2011SP-II-14
Ans: C
Note that $z=\dfrac{kx}{y}$, where $k$ is a non-zero
… Read Note that $z=\dfrac{kx}{y}$, where $k$ is a non-zero
2011SP-II-15
Ans: B
Since the maximum absolute error of the three sides ar
… Read Since the maximum absolute error of the three sides ar
2011SP-II-16
Ans: B
In $\Delta OAB$, as $OA=AB$,
… Read In $\Delta OAB$, as $OA=AB$,
$\begin{array}{rcl}
\a
2011SP-II-17
Ans: A
For the right circular cylinder,
… Read For the right circular cylinder,
$\begin{array}{rc
2011SP-II-18
Ans: B
Consider the area of $ABCD$,
… Read Consider the area of $ABCD$,
$\begin{array}{rcl}
DT
2011SP-II-19
Ans: A
$\begin{array}{cl}
& \dfrac{\sin\theta}{\c
… Read $\begin{array}{cl}
& \dfrac{\sin\theta}{\c
2011SP-II-20
Ans: A
Add a point $G$ such that $AG\perp GF$. Note that
… Read Add a point $G$ such that $AG\perp GF$. Note that
$\beg