2012PP-II-02
Ans: C
$\begin{array}{rcl}
3a+1 & = & 3(b-2) \\
3
… Read $\begin{array}{rcl}
3a+1 & = & 3(b-2) \\
3
HKDSE-MATH - 2012PP
2012PP-II-03
Ans: A
$\begin{array}{cl}
& p^2 -q^2-p-q \\
= & (
… Read $\begin{array}{cl}
& p^2 -q^2-p-q \\
= & (
2012PP-II-04
Ans: D
$\begin{array}{rcl}
\mbox{LHS} & = & m(x-3
… Read $\begin{array}{rcl}
\mbox{LHS} & = & m(x-3
2012PP-II-05
Ans: D
By the remainder theorem, the remainder
… Read By the remainder theorem, the remainder
$\begin{arr
2012PP-II-06
Ans: C
The quadratic equation has equal roots, then $\Delta
… Read The quadratic equation has equal roots, then $\Delta
2012PP-II-07
Ans: B
I is true. $L_1$ is a vertical straight line and its $x$
… Read I is true. $L_1$ is a vertical straight line and its $x$
2012PP-II-08
Ans: D
I is false. According to the figure, the graph opens do
… Read I is false. According to the figure, the graph opens do
2012PP-II-09
Ans: A
$\begin{array}{rcl}
4x & & x-3 \\
3x &
… Read $\begin{array}{rcl}
4x & & x-3 \\
3x &
2012PP-II-10
Ans: B
The required price
… Read The required price
$\begin{array}{cl}
= & \$1~
2012PP-II-11
Ans: D
Let $c_0$ and $c_1$ be the original and new circumfere
… Read Let $c_0$ and $c_1$ be the original and new circumfere
2012PP-II-12
Ans: A
$\begin{array}{rcl}
(\alpha +\beta): (3\alpha-\b
… Read $\begin{array}{rcl}
(\alpha +\beta): (3\alpha-\b
2012PP-II-13
Ans: A
Note that $z=\dfrac{kx}{y^2}$, where $k$ is a non-ze
… Read Note that $z=\dfrac{kx}{y^2}$, where $k$ is a non-ze
2012PP-II-14
Ans: B
$\begin{array}{cl}
& 0.009~049~999 \\
= &
… Read $\begin{array}{cl}
& 0.009~049~999 \\
= &
2012PP-II-15
Ans: C
Let $r\mbox{ cm}$ be the radius of the sector $OABC$.
… Read Let $r\mbox{ cm}$ be the radius of the sector $OABC$.
$
2012PP-II-16
Ans: D
The base radius
… Read The base radius
$\begin{array}{cl}
= & \sqrt{1
2012PP-II-17
Ans: C
Since $\Delta CEF \sim \Delta DAF$ with $DF=2CF$, the
… Read Since $\Delta CEF \sim \Delta DAF$ with $DF=2CF$, the
2012PP-II-18
Ans: A
… Read $AB$ and $DE$ are produced and let $X$ be the intersect
2012PP-II-19
Ans: D
In $\Delta ABC$,
… Read In $\Delta ABC$,
$\because AB=BC$,
$\therefore \ang
2012PP-II-20
Ans: C
In $\Delta ABD$,
… Read In $\Delta ABD$,
$\because AB$ is the diameter,
$\the
2012PP-II-21
Ans: C
Join $OB$ and $OC$. Let $\angle COD = x$.
… Read Join $OB$ and $OC$. Let $\angle COD = x$.
$\because \ov