2013-II-02
Ans: D
$\begin{array}{rcl}
\dfrac{y-1}{c} & = &
… Read $\begin{array}{rcl}
\dfrac{y-1}{c} & = &
$\begin{arra
$\begin{a
$\begin{array}{cl}
=
$\begin{array}{cl}
= & \
$\begin{array}
$\begin{array
$\begin{a
Since $AD:BC=2:3$ and $E$ is the mid-point
$\therefore \angle ADB = \angle D
Since the