2013-II-01
Ans: B
$\begin{array}{cl}
& (27\cdot 9^{n+1})^3 \\
=
… Read $\begin{array}{cl}
& (27\cdot 9^{n+1})^3 \\
=
HKDSE-MATH - 2013 - Paper 2
2013-II-02
Ans: D
$\begin{array}{rcl}
\dfrac{y-1}{c} & = &
… Read $\begin{array}{rcl}
\dfrac{y-1}{c} & = &
2013-II-03
Ans: D
$\begin{array}{cl}
& h\ell -k\ell + hm –
… Read $\begin{array}{cl}
& h\ell -k\ell + hm –
2013-II-04
Ans: C
$\begin{array}{cl}
& 0.050~454~5 \\
= & 0
… Read $\begin{array}{cl}
& 0.050~454~5 \\
= & 0
2013-II-05
Ans: A
Consider the first inequality, we have
… Read Consider the first inequality, we have
$\begin{arra
2013-II-06
Ans: C
$\begin{array}{rcl}
(x-k)^2 & = & 4k^2 \\
… Read $\begin{array}{rcl}
(x-k)^2 & = & 4k^2 \\
2013-II-07
Ans: B
Note that $b$ is the $y$-intercept of the graph. There
… Read Note that $b$ is the $y$-intercept of the graph. There
2013-II-08
Ans: A
$\begin{array}{rcl}
x(x+3a)+a & \equiv &
… Read $\begin{array}{rcl}
x(x+3a)+a & \equiv &
2013-II-09
Ans: D
Since $f(x)$ is divisible by $x+1$, we have
… Read Since $f(x)$ is divisible by $x+1$, we have
$\begin{a
2013-II-10
Ans: A
The cost of profit making car
… Read The cost of profit making car
$\begin{array}{cl}
= &#
2013-II-11
Ans: D
The required interest
… Read The required interest
$\begin{array}{cl}
= & \
2013-II-12
Ans: C
The area in the map $:$ the actual area
… Read The area in the map $:$ the actual area
$\begin{array}
2013-II-13
Ans: C
Let $z=\dfrac{kx}{\sqrt{y}}$, where $k$ is a non-ze
… Read Let $z=\dfrac{kx}{\sqrt{y}}$, where $k$ is a non-ze
2013-II-14
Ans: D
From the equation $x+ay+b=0$, we have
… Read From the equation $x+ay+b=0$, we have
$\begin{array
2013-II-15
Ans: B
The four axes of reflectional symmetry are as follow:
… Read The four axes of reflectional symmetry are as follow:
2013-II-16
Ans: B
Join $BC$ and $OC$, where $O$ is the centre of the semic
… Read Join $BC$ and $OC$, where $O$ is the centre of the semic
2013-II-17
Ans: B
The slant height of the right circular cone
… Read The slant height of the right circular cone
$\begin{a
2013-II-18
Ans: C
Join $AE$.
… Read Join $AE$.
Since $AD:BC=2:3$ and $E$ is the mid-point
2013-II-19
Ans: C
$\because AB//AD$,
… Read $\because AB//AD$,
$\therefore \angle ADB = \angle D
2013-II-20
Ans: D
Add a rectangle on the figure as shown below.
… Read Add a rectangle on the figure as shown below.
Since the