2017-II-22
Ans: D
In $\Delta BCE$,
… Read In $\Delta BCE$,
$\begin{array}{rcl}
\cos 40^\circ
$\begin{array}{rcl}
\cos 40^\circ
$\begin{arr
$\begin{array}{cl}
=
Since $DE$ is the tangent to the circle at $A
According t