2018-II-01
Ans: B
$\begin{array}{cl}
& \dfrac{8^{2n+1}}{4^{3
… Read $\begin{array}{cl}
& \dfrac{8^{2n+1}}{4^{3
HKDSE-MATH - 2018 - Paper 2
2018-II-02
Ans: D
$\begin{array}{rcl}
\dfrac{\alpha}{1-x} & =
… Read $\begin{array}{rcl}
\dfrac{\alpha}{1-x} & =
2018-II-03
Ans: C
$\begin{array}{cl}
& h^2 -6h – 4k^2 -12k
… Read $\begin{array}{cl}
& h^2 -6h – 4k^2 -12k
2018-II-04
Ans: A
$\begin{array}{cl}
& \dfrac{1}{3x + 7} –
… Read $\begin{array}{cl}
& \dfrac{1}{3x + 7} –
2018-II-05
Ans: A
A is true. Rewrite the equation of the graph to $y = -(x &
… Read A is true. Rewrite the equation of the graph to $y = -(x &
2018-II-06
Ans: D
I is true. Consider the slope of $L_1$.
… Read I is true. Consider the slope of $L_1$.
$\begin{array
2018-II-07
Ans: D
$\begin{array}{rcl}
f(2m – 1) & = &
… Read $\begin{array}{rcl}
f(2m – 1) & = &
2018-II-08
Ans: C
Since $g(x)$ is divisible by $x – 1$, by the fact
… Read Since $g(x)$ is divisible by $x – 1$, by the fact
2018-II-09
Ans: D
The required interest
… Read The required interest
$\begin{array}{cl}
= & 1
2018-II-10
Ans: B
Consider
… Read Consider
$\begin{array}{rcl}
3a & = & 4b \
2018-II-11
Ans: D
Let $w = \dfrac{k\sqrt{u}}{v^2}$, where $k$ is a non-
… Read Let $w = \dfrac{k\sqrt{u}}{v^2}$, where $k$ is a non-
2018-II-12
Ans: A
Consider
… Read Consider
$\begin{array}{rcl}
a_3 & = & a_
2018-II-13
Ans: C
Consider
… Read Consider
$\begin{array}{rcl}
\dfrac{1-2x}{3} �
2018-II-14
Ans: B
Note that the maximum absolute error of the measureme
… Read Note that the maximum absolute error of the measureme
2018-II-15
Ans: D
The base of the triangle base
… Read The base of the triangle base
$\begin{array}{cl}
= &#
2018-II-16
Ans: A
Note that $ABCD$ is a parallelogram, then $AD = BC$. He
… Read Note that $ABCD$ is a parallelogram, then $AD = BC$. He
2018-II-17
Ans: B
Since $OC \perp AD$, then $AE = DE$. Hence, we have
… Read Since $OC \perp AD$, then $AE = DE$. Hence, we have
$\be
2018-II-18
Ans: B
Consider $\Delta BCE$ and $\Delta DCF$.
… Read Consider $\Delta BCE$ and $\Delta DCF$.
$\begin{arr
2018-II-19
Ans: D
I is true. In $\Delta CDE$,
… Read I is true. In $\Delta CDE$,
$\begin{array}{rcll}
\an
2018-II-20
Ans: B
Note that $\angle FBE = 90^\circ$. Then by applying Py
… Read Note that $\angle FBE = 90^\circ$. Then by applying Py