2019-II-01
Ans: C
$\begin{array}{cl}
& (a-b)(a^2 +ab – b^
… Read $\begin{array}{cl}
& (a-b)(a^2 +ab – b^
HKDSE-MATH - 2019 - Paper 2
2019-II-02
Ans: D
$\begin{array}{cl}
& \dfrac{(6x^7)^2}{4x^5
… Read $\begin{array}{cl}
& \dfrac{(6x^7)^2}{4x^5
2019-II-03
Ans: B
$\left\{ \begin{array}{ll}
6x – 7y = 40 &
… Read $\left\{ \begin{array}{ll}
6x – 7y = 40 &
2019-II-04
Ans: C
$\begin{array}{rcl}
(x-8)(x+ \alpha) – 6 �
… Read $\begin{array}{rcl}
(x-8)(x+ \alpha) – 6 �
2019-II-05
Ans: A
$\begin{array}{rcl}
h & = & 3 – \dfr
… Read $\begin{array}{rcl}
h & = & 3 – \dfr
2019-II-06
Ans: D
A is not true.
… Read A is not true.
$\begin{array}{rcl}
0.06557 & = &
2019-II-07
Ans: B
Consider the first inequality.
… Read Consider the first inequality.
$\begin{array}{rcl
2019-II-08
Ans: C
$\begin{array}{cl}
& f(c) + f(-c) \\
= & [c
… Read $\begin{array}{cl}
& f(c) + f(-c) \\
= & [c
2019-II-09
Ans: D
Let $f(x) = 2x^4 +kx^3 -4x -16$. Since $f(x)$ is divisi
… Read Let $f(x) = 2x^4 +kx^3 -4x -16$. Since $f(x)$ is divisi
2019-II-10
Ans: A
I is true. Rewrite the equation to general form, we hav
… Read I is true. Rewrite the equation to general form, we hav
2019-II-11
Ans: C
The required amount
… Read The required amount
$\begin{array}{cl}
= & 650
2019-II-12
Ans: B
$\begin{array}{rcl}
\dfrac{\text{the total cost o
… Read $\begin{array}{rcl}
\dfrac{\text{the total cost o
2019-II-13
Ans: A
Let $z = \dfrac{kx^2}{\sqrt{y}}$, where $k$ is a non-
… Read Let $z = \dfrac{kx^2}{\sqrt{y}}$, where $k$ is a non-
2019-II-14
Ans: C
$\begin{array}{rcl}
T(1) & = & 6 \\
T(2) &#
… Read $\begin{array}{rcl}
T(1) & = & 6 \\
T(2) &#
2019-II-15
Ans: D
… Read The height of the lateral face
$\begin{array}{cl}
= &
2019-II-16
Ans: D
Since $ABCD$ is a parallelogram, $BC = AD$ (opp. sides
… Read Since $ABCD$ is a parallelogram, $BC = AD$ (opp. sides
2019-II-17
Ans: A
Let $x = \angle ACD$.
… Read Let $x = \angle ACD$.
In $\Delta BCD$,
$\begin{array}
2019-II-18
Ans: D
Consider $\Delta ADF$ and $\Delta AEC$. Since $AD = DE
… Read Consider $\Delta ADF$ and $\Delta AEC$. Since $AD = DE
2019-II-19
Ans: A
By applying the Pythagoras Theorem to $\Delta ABD$, w
… Read By applying the Pythagoras Theorem to $\Delta ABD$, w
2019-II-20
Ans: C
In $\Delta BEF$,
… Read In $\Delta BEF$,
$\begin{array}{rcll}
BF & = &#