2020-II-21
Ans: C
In $\Delta BCE$,
… Read In $\Delta BCE$,
$\begin{array}{cl}
& BE^2 + BC
$\begin{array}{cl}
& BE^2 + BC
Consider $\Delta ABC$. Since $\an
Note that
$\begin{array}{cl}
= & \dfrac{
$\begin{array}{|c|c|c
I m
II is true. The gra
$\begin{array}{cl}
Sub. $x=
Note that $4