2022-II-01
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& \alpha^2-\alpha-\beta
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& \alpha^2-\alpha-\beta
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& \dfrac{81^{2n+3}}{(27
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(x+3)^2+mx & \equiv
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(x-c)(x-4c) & = & (3
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\dfrac{2}{u} + \dfrac{3}{v} &
Note that the rounding method is rounding down. That m
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3y-5 < 5y +1 & \ldots \unicode{x2460} \\
5y +1 \le 11 & \ldots \unicode{x2461}
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A may not be true. Note that $f(k) = k^2 -k +1$.
$\begin{
Since $g(x)$ is divisible by $x+2a$, we have
$\begin{
I is true. Rewrite the function of the graph into gener
The required interest
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= & 8
Since $x:y=8:5$, then let $x=8k$ and $y=5k$, where $k
Let $u=\dfrac{k\sqrt{v}}{w}$, where $k\neq 0$.
I is
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T(1) & = & 8 \\
T(2)
Let $r\text{ cm}$ be the radius of the the hemisphere.
Let $O$ be the centre of the circle. $A$ and $B$ be the en
Join $PN$.
Let $x\text{ cm}^2$ be the area of $\Delta M
Since $ABCD$ is a rectangle, then we have
$\begin{arr
In $\Delta ABD$ and $\Delta CAE$,
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Denote the four vertices by $A$, $B$, $C$ and $D$ as sho